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Nimfa-mama [501]
3 years ago
9

The first-order reaction, so2cl2 → so2 + cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 k. what percentage of the init

ial amount of so2cl2 will remain after 2.00 hours?
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
4 0
For the 1st order reactions,rate constant (k) is mathematically expressed as

k = \frac{2.303}{t}log \frac{Co}{Ct}
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'

Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s

Therefore, we have
</span>2.20 × 10^-5 = \frac{2.303}{7200}log \frac{100}{Ct}
∴ log\frac{100}{Ct} = 0.06877
∴, \frac{100}{Ct} = 1.1716
∴, Ct = 85.35%

Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
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