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AleksAgata [21]
3 years ago
15

The following chemical equation is not balanced: Al + CuO Al2O3 + Cu When this chemical equation is correctly balanced, what is

the coefficient of the copper product?
Chemistry
2 answers:
Sergio039 [100]3 years ago
8 0
2Al + 3CuO ----> Al2O3 + 3Cu

So the answer is 3
Irina-Kira [14]3 years ago
3 0

<u>Answer:</u> The coefficient of copper is 3.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed, but it can only be transformed from one form to another form. This also means that total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side.

The given balanced chemical equation follows:

2Al+3CuO\rightarrow Al_2O_3+3Cu&#10;

By Stoichiometry of the reaction:

2 moles of aluminium reacts with 3 moles of copper oxide to produce 1 mole of aluminium oxide and 3 moles of copper.

Hence, the coefficient of copper is 3.

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qaws [65]
V= .768L= 76.8ml HCL
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3 years ago
What is the force exerted by the load being lifted is called?
ludmilkaskok [199]
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8 0
3 years ago
How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?
viva [34]

Answer:

The answer to your question is P = 0.18 atm

Explanation:

Data

mass of O₂ = 0.29 g

Volume = 2.3 l

Pressure = ?

Temperature = 9°C

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Convert the mass of O₂ to moles

                16 g of O₂ -------------------- 1 mol

                0.29 g of O₂ ----------------   x

                    x = (0.29 x 1)/16

                    x = 0.29/16

                    x = 0.018 moles

2.- Convert the temperature to °K

Temperature = 9 + 273 = 282°K

3.- Use the ideal gas law ro find the answer

              PV = nRT

-Solve for P

              P = nRT/V

-Substitution

              P = (0.018 x 0.082 x 282) / 2.3

-Simplification

              P = 0.416/2.3

-Result

               P = 0.18 atm

5 0
3 years ago
8 l of water at 19 ∘c are mixed with 1.1 l of water at 47 ∘c in an insulated container. what is the final temperature of the sys
stepladder [879]
1692.9 is the answer


5 0
3 years ago
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