Answer:
a= 31
b=92
c=44
Step-by-step explanation:
Answer:
$10 bill = 14 and $20 bill = 16.
Step-by-step explanation:
Given : A cashier has 30 bills, all of which are $10 or $20 bills. The total value of the money is $460.
To find : How many of each type of bill does the cashier have.
Solution : We have given that
A cashier has 30 bills
Let bill of $10 = x .
Bill of $20 = y .
Money of $10 = 10x .
Money of $20 = 20y.
Total bill
x + y = 30-------(1)
10x + 20y = 460-----(2)
On multiplying equation 1 by 10 and subtracting from equation 2.
10x + 20 y = 460
(-)10x +(-) 10 y = (-)300
______________
0 + 10 y = 160 .
On dividing by 10
y = 16 .
Plug y = 16 in equation 1
x + 16 = 30
On subtracting both sides by 16.
x = 30 - 16.
x = 14
Therefore, $10 bill = 14 and $20 bill = 16.
Answer:
144/91
Step-by-step explanation:
24/7 ÷ 13/6
Keep the first fraction the same, change the sign, and flip the last fraction to solve
24/7 × 6/13 = 144/91
Answer:
x < 19
Step-by-step explanation:
Given that,
An inequality 2x - 5 < 33.
LHS of the inequality is 2x - 5
RHS of the inequality is 33
LHS < RHS
i.e.
2x - 5 < 33
Add 5 to both sides of the inequality
2x - 5 +5 < 33+5
2x < 38
Divide both sides by 2.
x < 19
So, the value of x is less than 19.
Answer:
a = -2
Step-by-step explanation:
5 + 14a = 9a - 5
Subtract 9a from both sides of the equation
5 + 5a = -5
Subtract 5a from both sides of the equation
5 = -5 - 5a
Add 5 to both sides of the equation
10 = -5a
Divide both sides of the equation by -5
a = -2
Hope this was useful to you!
