Acceleration
On a velocity time graph, the y-axis is velocity, and the x-axis is time. So the slope is the change in velocity for every unit of change in time.
acceleration- the rate of change of velocity per unit of time.
hope this helps :)
I believe the answer is b. external stimulus
Answer:
It takes 6.52 s to complete the 150 m track.
Explanation:
Let's find the position of the cyclist during the acceleration.
![x_{1}=v_{0}t+0.5at^{2}](https://tex.z-dn.net/?f=x_%7B1%7D%3Dv_%7B0%7Dt%2B0.5at%5E%7B2%7D)
![x_{1}=0.5(3.8)(4.5)^{2}](https://tex.z-dn.net/?f=x_%7B1%7D%3D0.5%283.8%29%284.5%29%5E%7B2%7D)
![x_{1}=38.48\: m](https://tex.z-dn.net/?f=x_%7B1%7D%3D38.48%5C%3A%20m)
Now, the final speed at this distance will be:
![v_{f}=v_{0}+at](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7B0%7D%2Bat)
![v_{f}=3.8*4.5](https://tex.z-dn.net/?f=v_%7Bf%7D%3D3.8%2A4.5)
![v_{f}=17.1\: m/s](https://tex.z-dn.net/?f=v_%7Bf%7D%3D17.1%5C%3A%20m%2Fs)
Now, we know that x(tot) = 150 m, the remaining part will be:
![x_{2}=150-38.48=111.5\: m](https://tex.z-dn.net/?f=x_%7B2%7D%3D150-38.48%3D111.5%5C%3A%20m)
Therefore, the time is:
![t=\frac{x_{2}}{V_{f}}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bx_%7B2%7D%7D%7BV_%7Bf%7D%7D)
![t=\frac{111.5}{17.1}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B111.5%7D%7B17.1%7D)
![t=6.52\: s](https://tex.z-dn.net/?f=t%3D6.52%5C%3A%20s)
I hope it helps you!
Moving the body to do something