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3 years ago

Natural Resources Question 5

Physics

1 answer:

mars1129 [50]3 years ago

4 0

Answer:

-They will be available for many years.

Explanation:

The advantage of using renewable resources is that they will be available for many years.

Renewable resources have very fast turn over time for replenishing, therefore, they are available over an extended period time.

They are not used by consumption and so they will continually be available. This is different from the non-renewable resources which are depleted as they are being used up.

Examples of renewable resources are wind, water and air

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While on the moon, the Apollo astronauts enjoyed the effects of a gravity much smaller than that on

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Answer:

1.628 $\frac{m}{sec^{2} }$

Explanation:

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In this case

Neil is initially on the surface of moon and has a velocity of 1.51 $\frac{m}{sec}$ in upward direction.

⇒He has Kinetic energy= $K_{i}$ = $\frac{1}{2} m{v^{2} }$ J

But with respect to the surface of the moon,

where m=mass of moon

v=velocity of Neil

He has Potential energy= $P_{i}$ =0 J

At the highest point of his jump, his velocity =0

⇒ Kinetic energy= $K_{f}$ =0 J

His Potential energy with respect to the surface of moon= $P_{f}$ = $m \times g\times h$

where m=mass of moon

g= gravitational acceleration on moon

h=height from moon's surface

By Conservation Energy Principle

$K_{i}$ + $P_{i}$ = $K_{f}$ + $P_{f}$

$K_{i}$ +0=0+ $P_{f}$

$\frac{1}{2} m{v^{2} }$ = $m \times g\times h$

$\frac{v^{2} }{2}$ = $g\times h$

$\frac{1.5^{2} }{2}$ J= $g\times 0.7 m$

⇒ g = $\frac{1.14}{0.7}$ = 1.628 $\frac{m}{sec^{2} }$

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3 years ago

Calculate the frequency of the 3rd normal mode of a guitar string of length 40.0cm and mass 0.5g when stretched with a tension o

Alexandra [31]

Answer:

Explanation:

For third normal mode of vibration

l = $\frac{3\lambda}{2}$ , λ is wavelength , l is length of string .

.4 = $\frac{3\lambda}{2}$

λ = .267 m

velocity = $\sqrt{\frac{T}{m} }$

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m = .5 x 10⁻³ / 40 x 10⁻²

= .00125 kg / m

Putting the values

velocity = $\sqrt{\frac{80}{.00125} }$

= 253 m /s

frequency

= velocity / λ

= 253 / .267

= 947.5 Hz .

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Explanation:

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