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Troyanec [42]
3 years ago
7

How many of the first 1000 positive integers are multiples of both 4 and 5 but not 6 ?

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0
Let's begin by breaking  each number down into its prime factors:    4 = 2 x 2    5 = 5    6 = 2 x 3 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4, 5, and 6 by multiplying all common and unique prime factors of each number:    common prime factors: 2    unique prime factors:  2,5,3    LCM = 2 x 2 x 5 x 3 = 60 Next, let's determine how many times 60 goes into 10,000 (excluding remainder):    10,000/60 = 166 and 2/3    Multiples of ALL 3 numbers (4,5,6) = 166  Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4 and 5 by multiplying all common and unique prime factors of each number:    common prime factors:  none
    unique prime factors:  2 x 2 x 5
    LCM = 2 x 2 x 5 = 20 Next, let's determine how many times 20 goes into 10,000:
    10,000/20 = 500
    Multiples of BOTH numbers (4 and 5) = 500 Finally, let's subtract the multiples of ALL three numbers (4,5,6) from the multiples of BOTH numbers (4 and 5) to get our answer:   Multiples of ONLY numbers 4 and 5 (excluding 6):       500 - 166 = <span>334</span>
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Alright, lets get started.

One report takes to file an average of = 45 minutes

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= 540 * 75/100

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Hope it will help :)

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4 years ago
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Look for the bolded words ;'D

Step-by-step explanation:

The proportion setup would be 1/100=x/1063, since youre missing the inches from the actual model. By cross multiplying the equation to get 100x=1063, you'll now need to divide both sides of the equation by 100. This will get you 1063/100 inches, or you can get 10.63 inches by dividing 1063 by 100. You can also get 10 9/25 inches if you simplify the improper fraction...

....lol sorry for taking so long, but have a good day! :'D

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