A. define the variables : a = abby's miles, j = james' miles

b. a = j + 4......j = a - 4

c. a + j = 28
a = j + 4

d. (j + 4) + j = 28
2j + 4 = 28
2j = 28 - 4
2j = 24
j = 24/2
j = 12

a = j + 4
a = 12 + 4
a = 16

e. check..
a + j = 28
16 + 12 = 28
28 = 28 (correct)

solution is : abby's miles (a) = 16
james' miles (j) = 12

8 0

3 years ago

The temperature in fargo was -28 degrees on monday afternoon. by the evening it dropped an additional 15 degrees. what was the t

sashaice [31]

Step by step explanation: -28-15

When adding negative with positive it will always be negative so for this question, subtract -28 with 15 which would be -43. So -43 would be the temperature in the evening.

7 0

2 years ago

What is the radius of a sphere with a volume of 1/6 pie

Yakvenalex [24]

Answer:

$\large\boxed{the\ radius\ R=\dfrac{1}{2}}$

Step-by-step explanation:

The formula of a volume of a sphere:

$V=\dfrac{4}{3}\pi R^3$

We have

$V=\dfrac{1}{6}\pi$

Substitute:

$\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi$ divide both sides by π

$\dfrac{4}{3}R^3=\dfrac{1}{6}$ multiply both sides by 3

$3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}$

$4R^3=\dfrac{1}{2}$ divide both sides by 4

$R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}$