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MA_775_DIABLO [31]
3 years ago
11

At a point on the ground 46 feet from the foot of a tree, the angle of elevation of the top of the tree is 68 degrees. What is t

he height of the tree to the nearest foot?
Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0

Answer:

114 ft

Step-by-step explanation:

Imagine or construct a right triangle with the 46 ft leg lying on the ground.  This is the "adjacent side" of the triangle; it lies immediately adjacent to the 68 degree angle.  The side opposite this angle is h, the height of the tree.

The tangent function includes angle, opp side and adj side:

tan 68 degrees = opp / adj = h / (46 ft), and so:

(46 ft)*tan (68 degrees) = opp = h

Then the height of the tree is h = (46 ft)(2.47) = 114 ft

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2 years ago
ACDF is a trapezoid and
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Step-by-step explanation:

See the attached figure.

As shown: A C D F is a trapezoid and BE is a mid-segment.

The mid-segment of the trapezoid is the average of its bases.

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