Will give brainliest to right answer

I need the answers for 6,7,8,9,10,11 pls fast

Natalka [10]

Answer:

6) common denominator = 54

7) common denominator = 80

8) common denominator = 108

9) least common denominator = 10

10) least common denominator = 24

11) common denominator = 21

Step-by-step explanation:

6) common denominator of 1/6 , 1/9

example: A/B where A is de numerator and B is the denominator.

common denominators are numbers that have te same composition

1/6 , 1/9 ⇒ if we want to add this fractions we need to find the common denominator.

therefore: (1/6)*(9/9) , (1/9)*(6/6) ⇒ ((1*9)/(6*9)) . ((1*6)/(9*6)) ⇒ 9/54 , 6/54

the common denominator is 54

7) 3/8 , 3/10

(3*10)/(8*10) , (3*8)/(10*8) ⇒ 30/80 , 24/80

common denominator of this two fractions is 80

Note: We can see that the common denominator can be find just by multiplying the denominators. in 7) 6*9=54 and in 8) 10*8=80. This is because in this cases we are asked just for the common denominator

9) 1/9 , 5/12 ⇒ common denominator = 9*12 = 108

10) Least common denominator of 2/5 , 1/10

in this case is the smmallest number that the denominator have in common:

first, from 2/5: denominator=5

multiples of 5: ⇒5, 10, 15, .........

then from 1/10: denominator=10

multiples of 10 ⇒ 10, 20, 30,....

The least common denominator is the smalles number this two denominators have in common. We can see that this number is 10.

There are other ways because you should also think of it as the minimun common denominator. 5 =5*1 and 10 = 2*5 (minimun expresions)

the least minimun denominator willbe the one that includes all de numbers included in their minimum expresion without making it doble (just the amount of times to make the denominator number in each fraction).

therefore we would know that the least common denominator in this fractions is: 1*2*5 = 2*5 = 10

But just have fun and make it simple

10. least common denominator for: 5/6 , 3/8

first: 5/6 ⇒ denominator: 6, so ⇒ 6, 12, 18, 24, 30, 36.....

then: 3/8 ⇒ denominator: 8, so ⇒ 8, 16, 24. 32, 40....

least common denominator for this fractions is ⇒24

or also:

5/6 ⇒ denominator is 6 ⇒ 6=2*3

3/8 ⇒ denominator is 8 ⇒ 8=2*2*2

least common denominator for this fractions is ⇒ 2*2*2*3 =24

11. common denominator of: 1/3 , 2/7

because in this case 3 and 7 are in their minimum expresion ⇔ 3=1*3 & 7=1*7

we can jus find the common denominator by multiplying both denominators:

7*3=21

Hope it helps.

8 0

2 years ago

You roll a 6-sided die two times. What is the probability of rolling a number greater than 5 and then rolling a 1?

sasho [114]

Answer:

Step-by-step explanation:both are 1/6 of a chance

6 0

2 years ago

Read 2 more answers

Consider the sequence 6, 11, 16, 21 . . . . What is the 50th term in this sequence?

Damm [24]

Answer:

251

Step-by-step explanation:

Tn=5n+1

e.g.T1=5(1)+1

=6

e.g.T2=5(2)+1

=11

e.g.T3=5(3)+1

=16

e.g.T4=5(4)+1

=21

Answer:T50=5(50)+1

=251

5 0

2 years ago

Miriam makes 214 gallons of punch for a school event. How many 4‐ounce servings of punch can she serve ?

yawa3891 [41]

Convert gallons to ounces
There 128 ounces in 1 gallon
So you would multiply
(214gal)*(128oz/1gal)=27392 ounces

27392oz / 4 oz = 6848 cups

5 0

2 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

7 0

2 years ago