Question

Question help please these are them 3

Answer 1

Answer: 0

Step-by-step explanation:

$log_{m} 1 = x$

   1 = mˣ

   1 = m⁰

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Answer: $x = -\frac{2}{33}$

Step-by-step explanation:

log₁₀ (1 - 6x) = 2         restriction: 1 - 6x > 0    ⇒     x < $\frac{1}{6}$

        1 - 6x = 10²

        1 - 6x = 100

      -1             -1

           -6x = 99

            $\frac{-6x}{-6} = \frac{99}{-6}$

              x = $-\frac{2}{33}$

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Answer: $x = -\frac{3}{5}$

Step-by-step explanation:

$\frac{1}{\sqrt[5]{27} }$ = 3ˣ

$\frac{1}{\sqrt[5]{3^{3}} }$ = 3ˣ

$\frac{1}{3^{\frac{3}{5} } }$ = 3ˣ

$3^{-\frac{3}{5}$ = 3ˣ

$-\frac{3}{5} = x$

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Answer: $x = \frac{5}{9}$

Step-by-step explanation:

ln 2 + ln x = ln 5 + ln (4x - 2)

ln (2(x)) = ln (5(4x - 2))

     2x   =   5(4x - 2)

     2x   =   20x - 10

 -20x       -20x        

  -18x  =             -10

       $\frac{-18x}{-18} = \frac{-10}{-18}$

         $x = \frac{5}{9}$