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Evgen [1.6K]
3 years ago
13

He help help help hep

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
2. X=3
Explanation: You do the opposite of the number. Its a -3 which means subtract 3 so add 3.

6. X=15
Explanation: You do the same for 2 so do the opposite which would be 15.
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Write yhr equation in standard form of the line with m=3/4 and b=6
ozzi

Answer:

y = 3/4 x + 6

Step-by-step explanation:

y = mx + b

y = 3/4 x + 6

3 0
4 years ago
A box is supposed to have 150 folders in it. Clare counts only 147 folders in
VikaD [51]

Answer:

it's a 0.02% error.

147/150= 0.98% of the folders are there, making the error 0.02%

Step-by-step explanation:

5 0
3 years ago
4x – 3y=8<br> 2. 5x – 2y = -11
AlladinOne [14]

Answer:

x = -7

y =  - 12

Step-by-step explanation:

The given system is:

4x-3y=8

5x-2y=-11

We make x the subject in the top equation to get:

x =  \frac{3}{4}y + 2

Plug this expression for x in the bottom equation to get

5( \frac{3}{4}y + 2) - 2y=  - 11

We expand to obtain

\frac{15}{4} y + 10 - 2y =  - 11

Multiply through by 4

15y + 40 - 8y =  - 44

Group similar terms

15y - 8y =  - 44 - 40

7y =  - 84

y =  -  \frac{84}{7}  =-12

This means

x =  -12\times  \frac{3}{4}  + 2

x =  - 7

6 0
4 years ago
HELP ME PLS I NEED TO PASS THIS TEST OR I FAIL 8TH GRADE
SVETLANKA909090 [29]
<span>----
Solve for "x":
x + 4y = 24
x + 16 = 24
x = 8
-----------------
Solution: (8,4)</span>
7 0
3 years ago
Find g'​(t) for the function ​g(t) = 7/t^4
Alex17521 [72]

The differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵

<h3>What is differentiation?</h3>

The method of determining the derivative, or rate of change, of a function in mathematics.is termed as the differentiation.

Given that:-

g(t)= \dfrac{7}{t^4}

The derivative will be calculated as:-

g'(t)=7   \dfrac{d}{dt}(t^{-4})\\\\\\g'(t)=7\times (-4t^{-5})\\\\\\g'(t)=\dfrac{-28}{t^5}

Therefore the differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵

To know more about derivatives follow

brainly.com/question/954654

#SPJ1

3 0
2 years ago
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