All categories

3 years ago

Look at the digits to find the next to numbers 654, 664, 674, 684 the next two numbers are —, —

Mathematics

2 answers:

Ymorist [56]3 years ago

4 0

694 and 704 are next

dedylja [7]3 years ago

4 0

So what you are doing is simply adding 10 to each additional number. You can figure that out because you can subtract 664-654=10

So it would be 694, and 704. Hope this helps :)

You might be interested in

Let’s be together sad

Verdich [7]

Answer:

yes, lets be together sad. i am completely down for this.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Simplify radicals problems attached please help!

Finger [1]

Answer:

G7. (2√3)/3

G8. -2+√7

G9. (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

$\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}$

G8.

$\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2$

G9.

$\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}$

_____

<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0

3 years ago

Given: PKHE - inscribed, m∠E=120°<br> m∠EPK=51°, PF ∥EH<br> Find: m∠KPF, m∠H.

3241004551 [841]

Answer:

KPF = 9 and H = 129

Step-by-step explanation:

An inscribed quadrilateral in a circle has all diagonal angles add up to 180, so we can use this to find the angles of the quadrilateral.

H= 180-EPK and K = 180-E so H = 129 and K = 60

Now PF and EH are parallel, so PE is a transversal. That means FPE = 180 - E = 60. Now it's pretty easy to solve for KPF = FPE - EPK = 60 - 51 = 9.

Let me know if you don't see how I did any of this and I'll be happy to explain it..

3 0

3 years ago

Electricity. The current I in an electric circuit varies inversely with the resistance R. If a current of 60 amperes is

Irina18 [472]

Bbbhh. Cxfvvcgyiiknbvfds21111

3 0

2 years ago

I don't think I'm doing this right heeellppp

Feliz [49]

Any locker with a number that is a multiple of 8, 12, and 75 will contain all three animals.

The least common multiple of these three numbers is

$\mathrm{lcm}(8,12,75)=600$

and so any multiples of 600 between 1 and 3500 will contain all three animals. These are 600, 1200, 1800, 2400, and 3000.

Why is the LCM 600? You can determine that using the prime factorizations of the three given numbers:

$8=2^3$
$12=2^2\times3$
$75=3\times5^2$

The LCM can be obtained by multiplying as many prime numbers together as are needed to contain the prime factorizations of the three numbers. This is obtained with

$2^3\times3\times5^2=8\times3\times25=600$

(at least three 2s to get the 8; at least one 3 and two of the previous 2s to get 12; and at least two 5s along with the previous 3 to get 75)

8 0

3 years ago