You multiply then solve for y
<span>(–9.7 • 24) • (–0.25) = –9.7 • (24 • y)
</span>-232.8*(-0.25)=-232.8y
58.2=-232.8y
58.2/-232.8=-232.8y/-232.8
y= -0.25
Vbox-vspheres
vbox=, I assume we are dealing with l=w=h
so
v=lwh=12^3=1728
vsphere=(4/3)pir^3
r=3
vsphere=(4/3)pi3^3=4pi9=36pi
8 of them so
8 times 36pi=288pi or about 904.7786842338604526772412943845 cubic inches
vbox-sphere=1728-904.7786842338604526772412943845=823.2213157661395473227587056155
space filled by packing beads is about 823.22 cubic inches
beads percent is 823.2213157661395473227587056155/1728 times 100=47.64% filled by beads
Given:
In ΔKLM, l = 48 inches, ∠K=55° and ∠L=46°.
To find:
The length of k, to the nearest inch.
Solution:
According to Law of sine,
In ΔKLM, using law of sine, we get
On further simplification, we get
Approximate the value to the nearest inch.
Therefore, the length of k is 55 inch.
Answer:
2 Numbers; -10, and 10.
Step-by-step explanation:
