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Flura [38]
4 years ago
12

Solve |x| – 17 = 60 What is the correct answer

Mathematics
2 answers:
belka [17]4 years ago
6 0

Answer:

x=77

Step-by-step explanation:

Hope this helps!!!!

Kazeer [188]4 years ago
4 0

Answer:

x = 77,  x = -77

Step-by-step explanation:

|x| – 17 = 60

Add 17 to each side

|x| – 17+17 = 60+17

|x|  = 77

The absolute value equation has two solutions, one positive and one negative

x = 77,  x = -77

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Florence makes y cards in 3 minutes. how many cards does she make in 1 minute
Oduvanchick [21]

Answer:

y:3

y/3:1

She can make y/3 cards in one minute

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
4cx - 5c = -12x +d, c and d are integers. What is value of c and d?
Tems11 [23]
First, find out c
4c=-12, so c=-3
-5c=d, so d=15
3 0
4 years ago
f(x)= -7^2+8x+2 what is the value of the discriminant of f? How many x-intercepts does the graph of f have?
Lana71 [14]

I think it has one x-intercept which is (0, -47). I am not really sure though.

4 0
3 years ago
Given that the 3rd term in an arithmetic sequence is -2 and the 7th term is -10, tell me what the 1st term in the sequence is. E
Elenna [48]

Answer:

2

Step-by-step explanation:

a₃ = -2

a₇ = -10

The nth term of an arithmetic sequence is:

a = a₁ + d (n − 1)

Therefore:

-2 = a₁ + d (3 − 1) = a₁ + 2d

-10 = a₁ + d (7 − 1) = a₁ + 6d

Subtract the equations:

8 = -4d

d = -2

Plug into either equation to find the first term.

-2 = a₁ + 2(-2)

a₁ = 2

5 0
3 years ago
What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

5 0
3 years ago
Read 2 more answers
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