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Snowcat [4.5K]
3 years ago
12

The amount of money in Malik's bank account 3 years ago was $1,000. This year his balance is $1,900

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0
Each year his balance has increased by 300 dollars. 3 x $300 = $900
I assume this is the answer you are looking for.
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HELP FASTTTT Which graph shows the solution to the system of linear inequalities ?
Mice21 [21]
Well, we do not see the lines clearly (if they are dotted (inequality) or solid (inequality or equal) ), but we'll come back to this.

y<x+1  can be simplified to be y<x if we ignore the constants, so the valid part is BELOW the line, since (y<)

x-4y <=4
again, ignore the constants and simplify to 
x-y<0 or
y>x   so the valid part is ABOVE the line (since y>)

There are two graphs that satisfy BOTH conditions, pink (slope=1) at the bottom, and blue (slope = 1/4) on top, i.e. first and third graph.

For the absolute inequality (y<x+1), the red line must be dotted.
For the <= condition, the blue line must be solid.

As we cannot see the lines clearly, you will make the choice between the first and third graphs according to the previous paragraph.

4 0
2 years ago
Read 2 more answers
Increase 250ml by 86%
Alexandra [31]
250=100%
25=10%
12.5=5%
2.5=1%
25*8=200(80%)
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200+12=215(86%)
250+200=450(186%)
so 450ml is your answer
Hope this helped :)
6 0
3 years ago
Pleaseee help me out !!!
Dahasolnce [82]

Answer:

y = 16

Step-by-step explanation:

y = 11 - x

of x is -5, subtitute it into the equation

y = 11 - (-5)

y = 11 + 5

y = 16

8 0
2 years ago
Read 2 more answers
Please help Will give you the brainliest.
balu736 [363]

Answer: A.

Step-by-step explanation:

7 0
3 years ago
Can anyone help I’ll give you brainliest
Oduvanchick [21]

Answer:

Interest for 1 year is $80.50

Step-by-step explanation:

Simple interest is given by the formula

I =PRT

where I is the interest, P is the principal, R is the rate in decimal form, and T is the time.

P =3500

R=.023

T = 1     (1 year)

I = (3500) * (.023) (1)

I = 80.50

8 0
3 years ago
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