Question

Find area sector ACBD.... please and thank you

Answer 1

The sector is $\dfrac{360^\circ - 60^\circ}{360^\circ} = \dfrac 5 6$ of the circle so the area is

$\dfrac 5 6 \pi r^2 = \dfrac 5 6 \pi (10^2) = \dfrac{250 \pi}{3}$