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brilliants [131]
3 years ago
13

Draw a free-body diagram for the ear of a person properly wearing a mask. You may wish to refer to the figure

Physics
1 answer:
Schach [20]3 years ago
5 0

Answer:

  Rₓ - F cos θ = 0 ,     R_y - Fsin θ - W = 0

Explanation:

For this exercise we have a static equilibrium problem,

       ∑ F =0

In the attachment we have the forces involved, the weight (W) with vertical direction, the force towards the mask (F) and the reaction force of the ear that we will approximate by its vertical and horizontal components (Rₓ and R_y)

Let's use trigonometry to decompose the force F

       sin θ = Fₓ / F

        cos θ = F_y / F

       Fₓ = F sin θ

       F_y = F cos θ

we write the equations of equilibrium

X axis

           Rₓ - F cos θ = 0

Y axis

           R_y - Fsin θ - W = 0

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A 0.5 kg stone is raised from 1m to 2m height from the ground. what is the change in potential energy of the stone?
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Given: The mass of stone (m) = 0.5 kg

Raised from heights (h₁) = 1.0 m to (h₂) = 2.0 m

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where, all alphabets are in their usual meanings.

Now, we shall calculate the change in potential energy of the stone

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A 1400 kg wrecking ball hangs from a 20-m-long cable. the ball is pulled back until the cable makes an angle of 30.0 ∘ with the
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From the geometry of the problem, the 20 m-long cable creates the hypotenuse of a right triangle, with the extended of the other two sides of size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased by 20 m - 17.3 m = 2.7 m. 

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Answer:\dfrac{\pi}{2} ms^{-1}

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Let T be the time required to make one revolution.

Let r be the radius of the circular path.

Let d be the distance travelled by ball in one revolution.

As we know,the distance travelled in one revolution is the circumference of the circle.

So,d=2\pi r

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Let s be the speed of the ball.

s=\frac{d}{T}=\frac{\pi }{2}ms^{-1}

So,the speed of the ball is \frac{\pi }{2}ms^{-1}

5 0
3 years ago
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