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m_a_m_a [10]
3 years ago
5

What is the pressure amplitude for the threshold of human hearing?

Physics
2 answers:
Hoochie [10]3 years ago
5 0
The pressure amplitude for the threshold of human hearing is"<span> RMS sound pressure of </span>20 micropascals, corresponding to a sound intensity of 0.98 pW/m2<span> at </span>1 atmosphere<span> and 25 °C"</span>
Korolek [52]3 years ago
4 0

The answer is B,

1.0 x 10^-12 watts/meter^2

Source: http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/intens.html

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A constant torque of 3 Nm is applied to an unloaded motor at rest at time t = 0. The motor reaches a speed of 1,393 rpm in 4 s.
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Answer:

The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.

Explanation:

From Newton's Laws of Motion and Principle of Motion of D'Alembert, the net torque of a system (\tau), measured in Newton-meters, is:

\tau = I\cdot \alpha (1)

Where:

I - Moment of inertia, measured in Newton-meter-square seconds.

\alpha - Angular acceleration, measured in radians per square second.

If motor have an uniform acceleration, then we can calculate acceleration by this formula:

\alpha = \frac{\omega - \omega_{o}}{t} (2)

Where:

\omega_{o} - Initial angular speed, measured in radians per second.

\omega - Final angular speed, measured in radians per second.

t - Time, measured in seconds.

If we know that \tau = 3\,N\cdot m, \omega_{o} = 0\,\frac{rad}{s }, \omega = 145.875\,\frac{rad}{s} and t = 4\,s, then the moment of inertia of the motor is:

\alpha = \frac{145.875\,\frac{rad}{s}-0\,\frac{rad}{s}}{4\,s}

\alpha = 36.469\,\frac{rad}{s^{2}}

I = \frac{\tau}{\alpha}

I = \frac{3\,N\cdot m}{36.469\,\frac{rad}{s^{2}} }

I = 0.0823\,N\cdot m\cdot s^{2}

The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.

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How much pure gold (24/24) is to be added to 15.0 grams of 14 K gold (14/24) to obtain 18 K gold (18/24)?
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Answer:

10 gram gold is added

Explanation:

given data

pure gold = (24/24)

added = 15 grams

gold = 14 K  ( 14/24)

gold = 18 K ( 18/24)

to find out

How much pure gold added

solution

we know here that when we add gold to get 20 K gold or 22K

so we added here 15 gram 14 K

we consider here m is pure gold added

so by composition here

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