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sertanlavr [38]
3 years ago
14

The kinetic energy of a ball with the mass of 0.5 kg and a velocity of 10 m/s is what

Physics
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

25J

Explanation:

Kinetic energy = 1/2 mv²

Mass = m= 0.5kg

Velocity = v = 10m/s

K. E = 1/2 x 0.5 x 10 x 10

K. E = 0.5 x 5 x 10

K. E = 2.5 x 10

K. E = 25 J

The S. I unit of energy is joules with symbol J

I hope this was helpful, Please mark as brainliest

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Ivahew [28]
B trend line is right
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3 years ago
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A top of rotational inertia 4.0 kg m2 receives a torque of 2.4 nm from a physics professor. the angular acceleration of the body
Tanzania [10]

Angular acceleration is simply the ratio of the Torque over the rotation inertia, that is:

Angular acceleration = Torque / Rotational inertia

 

So substituting the values:

Angular acceleration = 2.4 N m / 4.0 kg m2

<span>Angular acceleration = 0.7 rad/s^2</span>

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3 years ago
What law states force is dependent on the mass and acceleration of an object
UNO [17]

Answer:

Newton's second law of motion

Explanation:

Newton's second law of motion can be stated  

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

in another form,

Force = mass * acceleration

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3 years ago
If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he
forsale [732]
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q= mC_s \Delta T
where m is the mass of the substance, Cs is its specific heat capacity and \Delta T is the increase of temperature.

If we re-arrange the formula, we get
C_s =  \frac{Q}{m \Delta T}
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
C_s =  \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C
6 0
3 years ago
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Planetary orbits... are spaced more closely together as they get further from the Sun. are evenly spaced throughout the solar sy
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Answer:

E) are almost circular, with low eccentricities.

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Kepler's laws establish that:

All the planets revolve around the Sun in an elliptic orbit, with the Sun in one of the focus (Kepler's first law).

A planet describes equal areas in equal times (Kepler's second law).

The square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit (Kepler's third law).

T^{2} = a^{3}

Where T is the period of revolution and a is the semi-major axis.

Planets orbit around the Sun in an ellipse with the Sun in one of the focus. Because of that, it is not possible to the Sun to be at the center of the orbit, as the statement on option "C" says.

However, those orbits have low eccentricities (remember that an eccentricity = 0 corresponds to a circle)

In some moments of their orbit, planets will be closer to the Sun (known as perihelion). According with Kepler's second law to complete the same area in the same time, they have to speed up at their perihelion and slow down at their aphelion (point farther from the Sun in their orbit).

Therefore, option A and B can not be true.

In the celestial sphere, the path that the Sun moves in a period of a year is called ecliptic, and planets pass very closely to that path.  

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3 years ago
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