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Sunny_sXe [5.5K]
3 years ago
5

Help me please I'm not good At math

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0
What exactly do you need help with

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4. Gabby ate 25 % of a whole pepperoni pizza.
mart [117]

Answer:

There is 5/8 left for Mohamed to eat.

Step-by-step explanation:

Let's put everything into fractions of 1/8. knowing that 25% is 1/4 or 2/8, 1/8 + 2/8= 3/8. and to find the answer, you need to subtract 3/8 from 8/8 or 1.

As a result, 5/8.

3 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!!!!!
Anna35 [415]
4y^2+2=(4y\cdot4y)+2\\
4y^2+2=16y^2+2 \leftarrow \text{not identity}\\\\
4y^2+2=(4y+y)+2\\
4y^2+2=5y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y+y)+2\\
4y^2+2=8y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y\cdot y)+2\\
4y^2+2=4y^2+2 \leftarrow \text{identity}

So it's D.
8 0
3 years ago
Please help solve the given system of equations: x = -3
prohojiy [21]
Where does if have the bracerts





|   |
8 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
Which is the correct answer A B C D ?
storchak [24]

Answer: c

Step-by-step explanation:

3 0
2 years ago
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