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3 years ago

If the first term is 5 and the common difference is -3?

Mathematics

1 answer:

Doss [256]3 years ago

6 0

-2 is the answer
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ANSWER ASAP!!! PLEASE... I really need an answer ;-; ..

arsen [322]

1:59 pm is 13:59, 13:59 - 06:31 = 07:28

Answer: 7 hours 28 minutes to reply

2.,3. On a "date" at 6:31 am when he already has a girlfriend? Dump him and don't look back.

3 0

3 years ago

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Tom's mark of a maths test was 68.This was 20% worse than his mark in English.what was Tom's English mark ?

Shkiper50 [21]

98 would be his english mark

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3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

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Classify the number as rational or irrational.

erastova [34]

2.876 is rational. It can be expressed as 2876/1000.
-(sqrt(16)) is rational. It can be expressed as -4/1.
3pi is irrational. Pi cannot be expressed as a fraction.
23/40 is rational. It can be expressed as 23/40.

Have a nice day!

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3 years ago

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Rewrite each pair of unlike fractions as like fractions 1/2,1/4

yuradex [85]

Example:
1. 2/3,3/4
2. 3/5,1/2 
3. 2/5,1/3 
4. 5.6,4.5 
5. 1/2,2/3 
6. 3/7,2/3 
7. 1/3,3/10 
8. 2/5,3/7

Answer:

1. 8/12, 9/12
2. 6/10, 5/10 
3. 6/15, 5/15 
4. 25/30, 24/30 
5. 3/6, 4/6 
6. 9/21, 14/21 
7. 10/30, 9/30 
8. 14/35, 15/35

5 0

3 years ago