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Gnom [1K]
3 years ago
13

The height of 5th grade boys is normally distributed with mean μ=57 inches and standard deviation σ=2 inches. What is the probab

ility that the height of a randomly selected 5th grade boy will be between 53 inches and 61 inches?
Mathematics
1 answer:
Wittaler [7]3 years ago
8 0

Answer:

0.9544

Step-by-step explanation:

Mean =  μ=57

Standard deviation σ=2

Formula : z=\frac{x-\mu}{\sigma}

At x = 53

z=\frac{53-57}{2}

z=-2

Refer the z table

P(z<-2)=0.0228

At x = 61

z=\frac{61-57}{2}

z=2

Refer the z table

P(z<2)=0.9772

We are suppose to find the probability that the height of a randomly selected 5th grade boy will be between 53 inches and 61 inches.

P(53<x<61)=P(-2<z<2)=P(z<2)-P(z<-2) = 0.9772 - 0.0228=0.9544

Hence the probability that the height of a randomly selected 5th grade boy will be between 53 inches and 61 inches is 0.9544

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aleksklad [387]

Answer:

Option C is correct.

Equation of a line y=\frac{-2}{3}x+6 passing through (0,6) and (9,0).

Explanation:

Given the two points (0, 6) and (9 ,0).

To find the equation for the given two points (x_{1},y_{1}) and (x_{2},y_{2}) is,

y-y_{1}=m(x-x_{1}); where m is the slope and is given by:

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First find the slope m:

m=\frac{0-6}{9-0} =\frac{-6}{9} =\frac{-2}{3}

Substitute this value in equation of line:

y-6=\frac{-2}{3} (x-0) or

y-6=\frac{-2}{3} x

⇒ y=\frac{-2}{3}x+6

Therefore, the equation for the given point is:  y=\frac{-2}{3}x+6


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3 years ago
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Solvę for x. Assume that lines which appear tangent are tangent.
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