Answer:
16
Explanation:
The formula for the force of attraction between two charges is , where k is a constant, is the first charge, and is the second charge. As you can see, if the radius or distance increases by 2, the force decreases by 4 because it grows exponentially. However, if the charge of one of the particles increases by 2, the force between the two also increases by 2. Therefore, the new force will be 8*2=16. Hope this helps!
Answer:
Farm = 98.1 [N]
Explanation:
To solve this problem we must draw the respective free body diagram, with the forces acting on the monkey. An analysis of the sums on the y-axis must be performed, in this axis the weight is acting down and the forces of both arms pulling up.
Weight is defined as the product of mass by gravitational acceleration.
W = m*g
where:
m = mass = 20 [kg]
g = gravity acceleration = 9.81 [m/s²]
W = 196.2 [N] (units of Newtons)
As this force points down, the force of both arms must go up, therefore each arm exerts a force of:
Farm = 196.2 / 2
Farm = 98.1 [N]
Answer:
t = 3.38 s
Explanation:
We have,
Initial speed of the ball that leaves the student's hand is 16 m/s
Initially, the hand is 1.90 m above the ground.
It is required to find the time for which the ball in the air before it hits the ground. We can use the equation of kinematics as :
Here, and a=-g
The equation become:
After rearranging we get the above equation as :
It is a quadratic equation, we need to find the value of t. On solving the above equation, we get :
t = -0.115 s and t = 3.38 s (ignore t = -0.115 s )
So, the ball is in air for 3.38 seconds before it hits the ground.
grams, kilograms, pounds for mass
newtons for weight