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Rus_ich [418]
3 years ago
7

A ball rolls on a carpet. The ball experiences friction as it rolls. How will friction affect

Physics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

A- The ball experiences an unbalanced force and will slow down.

Explanation:

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Describe the structure of an atom.
Maurinko [17]
A as an atom contains a nucleus where protons and neutrons are present. Electrons orbit the nucleus in paths called orbital
5 0
3 years ago
MATHPHYS PLEASE HELP
solmaris [256]

Explanation:

Momentum is mass times speed.

p = mv

a) p = (1500 kg) (25.0 m/s) = 37,500 kg m/s

b) p = (40,000 kg) (1.00 m/s) = 40,000 kg m/s

The truck has more linear momentum.

Momentum in the y direction:

pᵧ = (1500 kg) (25.0 m/s) = 37,500 kg m/s

Momentum in the x direction:

pₓ = (1500 kg) (15.0 m/s) = 22,500 kg m/s

Total linear momentum:

p² = pₓ² + pᵧ²

p² = (22,500 kg m/s)² + (37,500 kg m/s)²

p = 43,700 kg m/s

3 0
3 years ago
Read 2 more answers
(b) During one day, 250 kg of water is pumped through
ser-zykov [4K]

Answer: The energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

Explanation:

Given: Mass = 250 kg

Initial temperature = 16^{o}C

Final temperature = 38^{o}C

Specific heat capacity = 4200 J/kg^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J

Thus, we can conclude that the energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

4 0
2 years ago
Two metal plates 4 cm long are held horizontally 3 cm apart in a vacuum, one being vertically above other. The upper plate is at
kati45 [8]

Answer:

the answer to your question is 4 cm long

Explanation:

5 0
3 years ago
The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?
sp2606 [1]

Answer:

2. How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of aluminum is 0.90 J/gºC? c=0.90J/g. 9 (2 sigs.)

Explanation:

8 0
3 years ago
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