1.which of the following are true.

A process with a negative change in enthalpy and a negative change in entropy will generally be:________

valentina_108 [34]

A process with a negative change in enthalpy and a negative change in entropy will generally be: spontaneous.

<h3>Gibbs free energy:</h3>

Since the Gibbs free energy is a parameter that tells us whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) in this situation, we can describe it mathematically as:

ΔG = ΔH - TΔS

Therefore, any process with a negative change in enthalpy and a positive change in entropy will be spontaneous. If the enthalpy and the entropy are both negative, the subtraction becomes always negative, for which the Gibbs free energy is also negative.

One of the most crucial thermodynamic functions for the characterization of a system is the Gibbs free energy. It influences results like the voltage of an electrochemical cell and the equilibrium constant for a reversible reaction, among others.

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3 0

1 year ago

A sled with a mass of 32 kg is being pulled across the snow. If the friction force between the sled and the ground is 12 N, what

Sergeeva-Olga [200]

Answer:

Fa= 47.2N

Explanation:

3 0

3 years ago

suppose you are testing how the number of batteriesaffects bulb brightness.what heads would you use on the data table

Art [367]

   My estimate of brightness,
Number of batteries       on a scale of 1 to 10

   1 very dim
   2 1
   3 1 and 1/2
   4 6
   5 10 for a second, then
   the bulb burned out
   and changed to zero.

5 0

3 years ago

(b) The efficiency of the pump which operates the fountain is 70%.

ruslelena [56]

Answer:

Power supplied to the pump is 980000 W or 980 KW

Note: The question is incomplete. The complete question is given below:

On a day with no wind, a fountain in Switzerland propels 30000 kg of water per minute to a height of 140 metres.

a)Calculate the power used in raising the water?

b)The efficiency of the pump which operates the fountain is 70%

calculate the power supplied to the pump?

Explanation:

Efficiency = Power output/Power input * 100%

Power output = work done/ time

where work done = mass * acceleration due to gravity (g) * height

time = 1 minute = 60 seconds

mass of water = 30000 kg, height = 140 meters, g = 9.8 m/s²

Then, work done = 30000 * 140 * 9.8 = 41160000 J

Power output then = 41160000 J / 60 s

Power output = 686000 W

The power input can then be derived from the formula of efficiency

Power input = (Power output * 100)/Efficiency

Power input = (100 * 686000) / 70

Power input = 980000 W

Therefore, power supplied to the pump is 980000 W or 980 KW

8 0

3 years ago

A helicopter flies parallel to the ground at an altitude of 1/2 kilometer and at a speed of 2 kilometers per minute. If the heli

Mashutka [201]

Answer: Hello there!

If we define the x-axis as the one parallel to the ground and y as the perpendicular ( or the height in this case) then you know that the y position of the helicopter is equal to 0.5 kilometers, and is constant.

And the x component is x = (2km/min)*t where t is in minutes, and we could define t = 0 when the helicopter is over the white house.

Also, in this case, we can define the position of the white house as y = 0 and x = 0

Then our position vector (x,y) for the helicopter is ( 2*t, 0.5) and the position of the white house is (0,0)

then the distance between the helicopter and the white house is:

$d(t) =I(2*t,0.5) - (0,0)I = I(2*t, 0.5)I= \sqrt{ ((2*t)^2 +0.5^2)}$

where the distance is calculated as the magnitude of the difference in the position between the two objects

Now we want to know the rate of change in the distance when t = 3.

This is equivalent to calculate the derivative of d(t) valuated in t = 3 minutes, this is d'(3)

then we need to derivate our equation:

$d'(t) = \frac{dd(t)}{dt} = \frac{d(\sqrt{ ((2*t)^2 +0.5^2)})}{dt} = 0.5*((2*t)^2 +0.5^2)^{-1/2} *4*t$

now we can replace t by 3, and see the value of the rate of change 3 minutes after the helicopter was directli over the white house:

$d'(3) = 0.5*((2*3)^2 +0.5^2)^{-1/2} *4*3 = 0.99$

The rate of change of the distance is 0.99 kilometers per minute square.

4 0

2 years ago