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sergij07 [2.7K]
3 years ago
10

A cat keeps eating to gain weight while a dog keeps doing exercise.Later, the cat's weight increases by 20% and the dog's weight

decrease by 10% such that their weights become the same. By what percentage is the cat weight less than the dog's original weight?​
Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

Step-by-step explanation:

We will call the dog's original weight d and the cat's c.  according to the problem 1.2c=.9d

1.2c is the cat's weight increased by 20% and .9d is the dog's weight decreased by 10%  Now we just solve this with algebra for the dog's original weight.

1.2c=.9d

(1.2/.9)c = d

(4/3)c = d

Now, this tells us that the dog's original weight was 4/3 of the cat's.or  about 33.33% larger

It kinda looks like the question is then asking what the cat's current weight is  in comparison to the dog's original.  If that's the case we need just one more step.  We want the dog's original weight and the cat's current weight in terms of the same variable.  Well, we have that.  

Current cat = 1.2c or 6/5, since we have the other in fractional form.

original dog = (4/3)c  

Now, what do we multiply the first to get to the second?  Well, we need common denominators.  15 is the lcm of 3 and 5, so we'll use that.

6/5 = 18/15 and 4/3 = 20/15

Nowwe want to know what we have to multiply 18 by to get to 20.  some algebra will find that.

18x=20

x = 20/18

x = 10/9

that's about 1.11, so the dog's original weight is about 11% higher than the cat's current weight.  

Hopefully that's the answer it wanted, if not or if there is something you didn't understand let me know.

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stepladder [879]

Answer: A. "Segment AD bisects angle CAB." is the right answer.

Step-by-step explanation:

Given : In ΔABC ,AC≅AB.

⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )

Now in ΔACD and ΔABD

AD=AD (common)....(2)

Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.

If AD bisects ∠CAB then ∠CAD=∠BAD..(3)

Now again Now in ΔACD and ΔABD

∠ACB=∠CBA [from (1)]

AD=AD [common]

∠CAD=∠BAD [from (3)]

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3 years ago
What is the equation of a line passing between the points below? (-3,1) (5,-7)
kirill [66]

Answer:

Ax + Ay + 2A = 0 for any nonzero A, for example (A=1): x + y + 2 = 0

Step-by-step explanation:

The equation of a line is

Ax + By + C = 0

so we know that:

A*-3 + B*1 + C = 0

A*5 + B*-7 + C = 0

Let's subtract one from the other:

A*(-3 - 5) + B*(1 + -7) = 0

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B = A

Let's input B = A into the first two equations

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checks out

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2 years ago
How should this relationship be classified?
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Answer:

Domain = -2, range = -5

Domain =>0, range = 0

domain = 2, range = 5

let y =>f(x)

It can be seen that Function can be linear having common difference 2

F(x) = 2x + 1 for x>0

is satisfied for above values

let's check

F(2) = 2(2)+1 = 4+1 = 5 As given

For x<0 , F(x) = 2x -1

f(-2)= 2(-2) -1= -4-1= -5 As given

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2 years ago
Figure not drawn to scale.
DerKrebs [107]
Though you do not provide a diagram, I am going to give this a try by assuming that O is the center of the circle, OA is a radius, and angle AOB is a central angle that measures 88 degrees.

We want to find out the area of sector AOB. First, we need to find the area of the entire circle. The area of a circle is given by A= \pi  r^{2} and since the radius of this circle is equal to 1, the area is \pi ( 1^{2} )= \pi

Next we need to know what fraction of the circle sector AOB represents. The distance around the circle is 360 degrees but the central angle that intercepts arc AB is 88 degrees. That meas that the fraction of the circle the sector represents is given by \frac{88}{360}= \frac{11}{45}

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see explanation

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(1)

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