Answer:
Probability that the son will be:
color-blind = 1/2
blue eyed = 1/8
blue eyed and color-blind = 1/16
Explanation:
Mother : BbXcX
Father : BbXY
Colorblindness is X linked recessive trait hence will be caused when the son has XcY genotype.
XcX X XY :
Xc X
X XcX XX
Y XcY XY
Half of the sons will have normal vision and other half will be colorblind hence, there is 1/2 probability that the son will be colorblind.
Eye color is autosomal trait and blue color will be produced when the child has bb genotype.
Bb X Bb :
B b
B BB Bb
b Bb bb
1/4 of the children will have blue eyes. Since half of the children are expected to be males, 1/4 * 1/2 = 1/8 sons are expected to have blue eyes.
Probability of a son being blue eyed and color blind will be :
1/8 * 1/2 = 1/16
Im almost certain the answer is D but theres a chance I might be wrong
If two homozygous plants with contrasting traits are crossed, the
expected genotypes for the offspring will be heterozygous. The
dominant trait would be expressed, but they'd be carriers for the
recessive trait.
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I believe the answer is A
A graphic that shows the number of organisms in each trophic level of the ecosystem is called a (c) number pyramid. It is in a form of a pyramid and the bottom indicates the largest number of the organisms. It could also be a source of the quantitative analysis of the ecosystem.
