Answer:
Step 1. A carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.
Step 2. The hydroxyethyl group is oxidized to an acetyl group, and the electrons are picked up by NAD+, forming NADH (the reduced form of NAD+). The high- energy electrons from NADH will be used later by the cell to generate ATP for energy.
Step 3. The enzyme-bound acetyl group is transferred to CoA, producing a molecule of acetyl CoA. This molecule of acetyl CoA is then further converted to be used in the next pathway of metabolism, the citric acid cycle.
Answer:A. the same number of chromosomes as was contained in the zygote.
Explanation:a zygote is formed when the sperm fertilize the egg .
After fertilization,the zygote undergoes cleavage.cleavage is the mitotic Division of the cells of a zygote to produce daughter cells.
These daughter cells are called blastomere,which contains the same number of chromosomes as the parent cells.the cells formed do not grow in size but continues to divide, forming a mass of cells.
This mass may be solid at first but as cleavage continues,the cells move away from the center,leaving a fluid filled cavity in the middle (blastocoel).
The mass of cells are called blastula.
Mitosis splits one cell into two of the same cell, and the more cells you have, the larger an organism can be.
