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zheka24 [161]
2 years ago
7

Write the first five terms of the sequence defined by the explicit formula

Mathematics
2 answers:
Gwar [14]2 years ago
8 0

The correct answer  is: 19, 13, 3, -11, -29


denis-greek [22]2 years ago
5 0

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

a_n=21-2n^2

So to find the first five terms of this sequence, we will substitute the values of n (num here in the given formula:

a_1=21-2(1)^2\\\\a_1=19


a_2=21-2(2)^2\\\\a_2=13


a_3=21-2(3)^2\\\\a_3=3


a_4=21-2(4)^2\\\\a_4=-11


a_5=21-2(5)^2\\\\a_5=-29

Therefore, the first five terms of the sequence defined by the explicit formula a_n=21-2n^2 are 19, 13, 3, -11, -29.


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natima [27]

Answer:

x=5

Step-by-step explanation:

That is your answer .

First you do 4x-3+3=2x+7+3

then,4x=2x+10,then

subtract 2x from both side

4x-2x=2x+10-2x

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2x=10

divide both sides by 2 2x/2=10/2

simplfy and you get x=5

Hope this helps :)

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Step-by-step explanation:

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Step-by-step explanation:

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