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3 years ago

Write the first five terms of the sequence defined by the explicit formula

Mathematics

2 answers:

Gwar [14]3 years ago

8 0

The correct answer is: 19, 13, 3, -11, -29

denis-greek [22]3 years ago

5 0

Answer:

The correct answer option is: 19, 13, 3, -11, -29.

Step-by-step explanation:

We are given the following explicit formula for an arithmetic sequence:

$a_n=21-2n^2$

So to find the first five terms of this sequence, we will substitute the values of $n$ (num here in the given formula:

$a_1=21-2(1)^2\\\\a_1=19$

$a_2=21-2(2)^2\\\\a_2=13$

$a_3=21-2(3)^2\\\\a_3=3$

$a_4=21-2(4)^2\\\\a_4=-11$

$a_5=21-2(5)^2\\\\a_5=-29$

Therefore, the first five terms of the sequence defined by the explicit formula $a_n=21-2n^2$ are 19, 13, 3, -11, -29.

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Read 2 more answers

Twice the difference of a number c and forty.

dybincka [34]

Answer:

Equation ----> 2(c - 40)

c = -40

Step-by-step explanation:

2(c - 40)

= (2c) - (80)

= 2c - 80