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faust18 [17]
3 years ago
7

Which expression correctly represents “six more than the quotient of three and a number, decreased by eight”? 6 + StartFraction

3 Over n EndFraction minus 8 6 + StartFraction n Over 3 EndFraction minus 8 6 + StartFraction 3 Over n EndFraction + 8 6 + StartFraction n Over 3 EndFraction + 8
Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

(3/x +6)-8

Step-by-step explanation:

The given statement is

"Six more than the quotient of three and a number, decreased by eight".

"Six more than" indicates the sum between the quotient and 6.

"The quotient of three and a number" indicates a fraction where the numerator is 3 and the denominator is , a number.

"Decreased by eight" indicates a subtraction between the quotient an 8 units".

If we unit all parts of the statements, we would have

The parenthesis just indicates the order of the operations as the problem states.

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What percent of 950 is 2​
Dima020 [189]

Answer: 0.21%

Step-by-step explanation: Please mark me brainlist

Step 1: We make the assumption that 950 is 100% since it is our output value.

Step 2: We next represent the value we seek with x

Step 3: From step 1, it follows that 100% = 950

Step 4: In the same vein x% = 2

Step 5: This gives us a pair of simple equations: 100% = 950(1)

x% = 2(2)
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have
100%/x% = 950/2

Step 7: Taking the inverse (or reciprocal) of both sides yields
x%/100%/ 2/950
---> 0.21%

6 0
2 years ago
* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both
Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective n^{th} terms as following:

Sequence A. 3n - 2

Sequence B. 10 - 2n

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the n^{th} terms of the respective sequences as equal and let us verify that.

3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}

When we talk about n^{th} terms, n here is a whole number not a fractional number.

But as per the statement as stated by Sally n is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0
2 years ago
Hello plz solve this question whoever solves best gets brainlest and points any links will be reported thank you
Drupady [299]

Answer:

D is correct

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How would i plot this on a graph??
professor190 [17]

Step-by-step explanation:

This is in the form of

h(x) = y

in this case, x is 1 and y is 7. So ourbpoint would be (1,7.)

5 0
3 years ago
Find the midpoint of the coordinates (-2,1) and (4,-4)
kow [346]
  • (-2,1)
  • (4,-4)

\\ \rm\longmapsto P(x,y)

\\ \rm\longmapsto \left(\dfrac{-2+4}{2},\dfrac{1-4}{2}\right)

\\ \rm\longmapsto \left(\dfrac{2}{2},\dfrac{-3}{2}\right)

\\ \rm\longmapsto \left(1,\dfrac{-3}{2}\right)

6 0
3 years ago
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