Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Answer:
The slope is 3 and the y intercept is -7/4
Step-by-step explanation:
We need to get the equation in the form
y = mx+b where m is the slope and b is the y intercept
12x - 4y =7
Subtract 12x from each side
12x-12x -4y = -12x +7
-4y = -12x+7
Divide each side by -4
-4y/-4 = -12x/-4 +7/-4
y = 3x + -7/4
The slope is 3 and the y intercept is -7/4
Answer:
2.5 dollars
Step-by-step explanation:
Discount points are normally a type of prepaid interests that lowers the interest on subsequent payments for mortgage borrowers pay.
Each of the points is given by:
1 point = 1% of the mortgage value.
Therefore,
Cost of discount points = 0.01*519,000*3 = $15,570
Cost of origination points = 0.01*519,000*2 = $10,380
In this regard, option B. is the correct answer on the cost of discount and origination points respectively.