We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral

This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
Answer:
9
Step-by-step explanation:
I think the answer would be 9 but I'm not for sure
Answer:
1,562.85
Step-by-step explanation:
34.5 times 45.3
4(x+x+7) x=1
4(1+1+7)
4+4+28 = 36
(-2x+7-4) x=2
-2(2)+7-4
-4+7-4 = -1
Step-by-step explanation:
22x13, 10x9, then both answers from the previous equations multiplied. Any questions?