Answer: 380km due south
Explanation:
Velocity is the rate of change of displacement. Mathematically
Velocity = displacement/time taken
Displacement = Velocity×time taken
Given velocity = 73km/hr
Time taken = 5.2hrs
Displacement = 73km/hr×5.2hrs
Displacement = 379.6km
Approximately 380km due South
Answer: 1.8 g
Explanation:
We start first, by calculating the amount of Helium
n = m/M
m = mass of Helium
M = molar mass if Helium
n = 2/4 = 0.5 moles
proceeding further, we use ideal gas law. PV = nRT
Then we have
P1V1/n1T1 = P2V2/n2T2
So that,
n2 = n1T1P2V2/P1V1T2
From the question, we know that, P1 = P2, and T1 = T2. So that,
n2 = n1v2/v1
n2 = (0.5 * 3.9) / 2
n2 = 1.95/2
n2 = 0.975 moles. With this, we can determine the mass, m2 of Helium
n = m/M
m = n * M
m = 0.975 * 3.9
m = 3.8
The difference between both masses are 3.8 - 2 = 1.8 g
Thus, 1.8 g of Helium was added to the cylinder
Answer:
The net magnetic flux through the rest of Earth's surface is
Explanation:
Given that,
Magnetic field = 42 μT
Area
We need to calculate the flux per unit area
We need to calculate the total earth's surface area
We need to calculate the rest of earth's area
Put the value into the formula
We need to calculate the net magnetic flux through the rest of Earth's surface
Hence, The net magnetic flux through the rest of Earth's surface is
Answer:
d) The image would be dimmer
Explanation:
When inverted image of an object is viewed on a screen from the side facing a converging lens, the
lens focuses the diverging, and blurred light rays from the distance object through refraction of the rays two times.Then the rays is converge by the double bending cl at a focal point behind the lens inorder for a sharper image to be be observed.
But when an opaque card is then introduced to cover only the upper half of the lens then the image becomes dimmer because of the reduction in the light intensity on the screen by 50%
Answer:
B
Explanation:
Potential energy.
Water stored in a dam have potential energy.We can allow the water to flow down and run a turbo generator to,produce current.