what happens to light when it falls upon a material that has a natural frequency equal to the frequency of the light?

Physics

1 answer:

mixas84 [53]1 year ago

7 0

The energy from the light is transferred to the material, causing it to vibrate and absorb the light.

What is energy?
In physics, energy is the quantitative quality that is transmitted to the a body or a physical system, and is discernible in the work performed as well as in the form of light and heat. The law of conservation states that although energy can change its form, it cannot be created or destroyed. Energy is indeed a conserved quantity. The International System of Units' (SI's) joule is the measurement unit for energy (J). A moving object's kinetic energy, a solid object's elastic energy, chemical energy caused by chemical reactions, and the potential energy that an object stores (for instance because of its position inside a field) are examples of common forms of energy.

When light falls upon a material that has a natural frequency equal to the frequency of the light, the light will be absorbed by the material. This is due to resonance, which occurs when the frequency of the light matches the natural frequency of the material. The energy from the light is transferred to the material, causing it to vibrate and absorb the light.

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The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t

Oksanka [162]

The acceleration due to gravity of Mars is $3.5\ m / s^{2}$

<u>Explanation:</u>

As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

$\text {Gravitational force of planet}=\frac{G M m}{R^{2}}$

Here, G is the gravitational constant, R is the radius of Mars and M, m is the mass of Mars and the object respectively..

Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

$Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}$

$Acceleration\ due\ to\ gravity\ of\ mars =\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}}$

$\text { Acceleration due to gravity of mars }=\frac{6.67259 \times 10^{-11} \times 6.1 \times 10^{23}}{3.4 \times 3.4 \times 10^{12}}=\frac{40.703 \times 10^{12}}{11.56 \times 10^{12}}$