Given: Normal pull of gravity g = 9.8 m/s²;
g = 0.855 m/s² (at a certain distance)
Universal gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²
Mass of the Earth Me = 5.98 x 10²⁴ Kg
Radius r = ?
g = GMe/r²
r = √GMe/g
r = √(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)/(0.855 m/s²)
r = 2.16 x 10⁷ m or
r = 21,610 Km
.
Answer:
W = 3.4x0³ J.
Explanation:
The work done by the man is given by the following equation:
(1)
<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>
We need to find first the total force Ft, which is:

<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°. </em>

Hence, the work is:
Therefore, the work done by the man is 3.4x10³ J.
I hope it helps you!
What impact ? Is there more to this question so I can help answer ?
Answer:
A - Watt
Explanation:
Watt is the unit of electrical power in a metric system, expressed in terms of energy per second, equal to the work done at a rate of 1 joule per second is
power formula is P = V × I,
where V is the voltage in a circuit
I is the current flowing through that circuit.
In the SI (metric) system, the units of power are watts.
Answer:
a. the ratio of the speed of light in a vacuum to the speed of light in the material it is passing though
Explanation:
When a light ray enters from one medium to another, it bends. This is because the speed of light decreases as it enters a medium having more optical density. The speed of light is maximum in vacuum.
The refractive index determines the optical density of a medium. It is the ratio of the speed of light in the vacuum (c) to the speed of light in the material it is passing through (v).
