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Anna [14]
2 years ago
12

What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?

Physics
1 answer:
serious [3.7K]2 years ago
3 0

Answer:

This is your answer

Explanation:

Actually I took this from go ogle

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if a student lifts their weight of 450 newtons up a set of stairs 5 meters high, how much work did they do?
irina1246 [14]

Answer:

2,250J

Explanation:

W = Fs = (450)(5) = 2,250

4 0
2 years ago
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Which excited electron has the lowest energy?
bearhunter [10]

Answer:

The lowest energy of electron is the ground state.

Explanation:

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2 years ago
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A small ball of mass 2.00 kilograms is moving at a velocity 1.50 meters/second. It hits a larger, stationary ball of mass 5.00 k
rewona [7]

The kinetic energy of the small ball before the collision is

                             KE  =  (1/2) (mass) (speed)²

                                     = (1/2) (2 kg) (1.5 m/s)

                                     =    (1 kg)  (2.25 m²/s²)

                                     =        2.25 joules.

Now is a good time to review the Law of Conservation of Energy:

                     Energy is never created or destroyed. 
                     If it seems that some energy disappeared,
                     it actually had to go somewhere.
                     And if it seems like some energy magically appeared,
                     it actually had to come from somewhere.

The small ball has 2.25 joules of kinetic energy before the collision.
If the small ball doesn't have a jet engine on it or a hamster inside,
and does not stop briefly to eat spinach, then there won't be any
more kinetic energy than that after the collision.  The large ball
and the small ball will just have to share the same 2.25 joules.

3 0
3 years ago
HELP PLEASE
4vir4ik [10]

Recall this kinematic equation:

a = \frac{Vi+Vf}{Δt}

This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).

a is the acceleration.

Vi is the initial velocity.

Vf is the final velocity.

Δt is the amount of elapsed time.


Given values:

Vi = 0 m/s (the car starts at rest).

Vf = 25 m/s.

Δt = 10 s


Substitute the terms in the equation with the given values and solve for a:

a = \frac{0+25}{10}

<h3>a = 2.5 m/s²</h3>
7 0
3 years ago
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Which equation could not be used to determine straight line acceration?
uranmaximum [27]

Answer:

the answer for the question is the last option

5 0
3 years ago
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