What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?
1 answer:
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Answer:
The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.
Explanation:
using Guass law,
(guessing that a cylinder of radius r and length L around wire such that wire is at centre )
E. A = qin / e0
E ( 2πr L ) = (1.56 x x L) / (8.85 x
)
E = (1.56 x ) / (2πr x 8.85 x
)
so 2.40 = (1.54 x ) / (2πr x 8.85 x
)
2.40 (6.284r) = 0.174 x 10²
15.0816r = 17.4
r = 1.1537m