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Anna [14]
2 years ago
12

What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?

Physics
1 answer:
serious [3.7K]2 years ago
3 0

Answer:

This is your answer

Explanation:

Actually I took this from go ogle

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Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section
ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER  E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W /  ( E × π × P )     ...................1

put here all value

σ = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

1300 × 10^{-24} = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

solve it and we get W

W = 249.56 × 10^{-2}

so elastic partial width is 2.49 eV

8 0
3 years ago
In an experiment you measure a first-order red line for Hydrogen at an angle difference of ΔΘ = 22.78o. The diffraction grating
azamat

Answer:

a) wavelength = 656.3 nm

b)  the value of Rydberg's constant for this measurement is 1.097 × 10⁷ m⁻¹

Explanation:

Given that;

angle of diffraction Θₓ = 22.78°

incident angle Θ₁ = 0

slit separation d  = 5900 lines per cm = 1/5900 cm = 10⁻²/5900 m = 0.01/5900 m

order of diffraction n = 1

wavelength λ = ?

to find the wavelength, we use the expression

λ = d (sinΘ₁ + sinΘₓ) / n

To find the wavelength λ;

λ = 0.01/5900 × (sin0 + sin22.78° )

λ = 6.5626 × 10⁻⁷ m

λ = 656.3 x 10⁻⁹ m

∴ λ = 656.3 nm

b)

According Balnur's  series spectral lines; n₁ = 3, n₂ = 2 and

λ = R [ 1/n₂² - 1/n₁²]

where  R is Rydberg's constant

from λ = R [ 1/n₂² - 1/n₁²]

R = 1/λ [n₂²n₁² / n₁² - n₂²]

R = 10⁹/ 656.3 [ 9 × 4 / 9 - 4 ]

R = 1.097 × 10⁷ m⁻¹

Therefore the value of Rydberg's constant for this measurement is 1.097 × 10⁷ m⁻¹

4 0
3 years ago
Newton's ____ law of motion explains why objects in the back of a truck would keep sliding forward if the truck stopped suddenly
Paraphin [41]

Answer:

1st

Explanation:

6 0
3 years ago
Read 2 more answers
A box of mass 64 kg is at rest on a horizontal frictionless surface. A constant horizontal force F~ then acts on the box and acc
iren2701 [21]

Answer:

The correct answer is;

The magnitude of the force is 35.12 N

Explanation:

To solve the question, we note that the friction is zero and the force causes motion of a stationary mass

One of the equations of motion is required such as

v² = u² + 2× a× s

Where

v = Final velocity = 5.93 m/s

u = Initial velocity = 0 m/s , object at rest

a = acceleration

s = distance moved = 32 meters

But v = Distance/Time = 32 m /5.4 s = 5.93 m/s

Therefore

5.93² = 2×a×32

or a = 35.12/ 64 = 0.55 m/s²

Therefore Force F = Mass m × Acceleration a

Where mass m = 64 kg

Therefore F = 64 kg×0.55 m/s² = 35.12 N

3 0
3 years ago
What is the Coriolis Force?
lys-0071 [83]

It's a virtual force ... one that seems to be there but isn't really there.

When something tries to fly or flow straight, through a rotating neighborhood, it ends up flying or flowing in a curved path, AS IF there were a force acting on it to make it curve. THAT apparent force is the Coriolis force.

It's what makes air, flowing away from high pressure or into low pressure, form the big rotating pressure systems on the rotating Earth.

7 0
3 years ago
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