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3 years ago

How do sound waves travel through a medium?

Physics

1 answer:

VARVARA [1.3K]3 years ago

3 0

Answer:

Sound waves need to travel through a medium such as solids, liquids and gases. The sound waves move through each of these mediums by vibrating the molecules in the matter. The molecules in solids are packed very tightly. ... Sound travels about four times faster and farther in water than it does in air

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The Hubble Telescope The Hubble Telescope is a large telescope that orbits Earth. It was named after Edwin Hubble. Hubble was an

Marrrta [24]

Quoting from the article itself:

"Since it is above Earth's atmosphere, it gives us clearer pictures of space than telescopes on Earth can."

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3 years ago

Ali mixes 20g of Sodium Chloride in 100g of water at 15 Degree °C. Calculate the mass of the solution

Lera25 [3.4K]

Answer:

The mass of the solution is 120 g.

Explanation:

The mass of the solution is given by:

$m_{sol} = m_{1} + m_{2}$

Where:

$m_{sol}$ : is the mass of the solution

$m_{1}$ : is the mass of the solvent

$m_{2}$ : is the mass of the solute

In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.

Hence, the mass of the solution is:

$m_{sol} = m_{1} + m_{2} = 100 g + 20 g = 120 g$

I hope it helps you!

7 0

3 years ago

When you stand outside your are standing in the, Stratosphere. Troposphere. Mesosphere no

AVprozaik [17]

Uhhh I’m not really sure of the answer i think it’s stratosphere

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3 years ago

MIDDLE SCHOOL: What are the three types of energy used when cleaning? (Please write them in order of occurrence)

tankabanditka [31]

Answer:

Chemical, mechanical, thermal i guess

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3 years ago

A 3 kg penguin is pushed by his penguin friends who give him an initial speed vo at the top of a 30 m hill. The penguin is hopin

Strike441 [17]

Answer:

This question can be answered by using conversation of energy.

$K_1 + U_1 = K_2 + U_2$

$\frac{1}{2}mv_{0}^2 + mgh_1 = 0 + mgh_2$

$\frac{1}{2}(3)v_0^2 + (3)(9.8)(30) = (3)(9.8)(45)\\\frac{1}{2}(3)v_0^2 = 441\\v_0^2 = 294\\v_0 = 17.14 m/s$

Explanation:

Note that we take $K_2 = 0$ because we are looking for the minimum initial speed for the penguin to reach the top of the second hill. Any other speed more than this will already be enough for him.

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3 years ago