3 years ago

A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?

Physics

1 answer:

Blababa [14]3 years ago

5 0

Answer:

Explanation:

$V^2=V^2_o+2a(x_f-x_i)$

$28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2$

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