All categories

3 years ago

If mzA is less than 90°, then ZA is an acute angle. mzA = 75°. What can

Mathematics

1 answer:

Sauron [17]3 years ago

7 0

Answer:

ZA is acute

Step-by-step explanation:

Here, we are interested in knowing what can be concluded given the information in the question.

Firstly, a definition was given for angles which are less than 90. Afterwards, a given value was set for the angle.

Since the given angle is less than 90, we can identify that that the value of the unknown angle is acute, which gives our answer

You might be interested in

Use Order of Operations to simplify the following:

allochka39001 [22]

Answer:

where is simplify question

7 0

3 years ago

30 divided by 1.25 with work

vesna_86 [32]

Answer:

Step-by-step explanation:

If you need an explaination you should immediatly remove yourself from the Gene pool, this is a 3rd grade question.

6 0

3 years ago

What is 0.28 and 2.65 as a fraction in simplest form? explain

Oksanka [162]

28/100=14/50=7/25 &the second one 2=200/100 so 200/100+65/100=265/100

265/100=53/20

5 0

3 years ago

Read 2 more answers

Find the area and the circumference of a circle with a diameter 8yrd.

nalin [4]

Answer:

Part 1) The area of the circle is $A=50.24\ yd^2$

Part 2) The circumference of the circle is $C=25.12\ yd$

Step-by-step explanation:

step 1

The area of a circle is equal to

$A=\pi r^{2}$

we have

$r=8/2=4\ yd$ ---> the radius is half the diameter

$\pi =3.14$

substitute

$A=(3.14)(4)^{2}$

$A=50.24\ yd^2$

step 2

The circumference of a circle is equal to

$C=\pi D$

we have

$D=8\ yd$

$\pi =3.14$

substitute

$C=(3.14)8$

$C=25.12\ yd$

3 0

3 years ago

Find the equation of the line passing through point (4,2) and perpendicular to AB

Setler [38]

Answer:

a. -⅓

b. 3

c. y = 3x - 10

Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

$Gradient = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 3}{7 - 1} = \frac{-2}{6} = -\frac{1}{3}$

Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

m = gradient/slope

We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

y - 2 = 3x - 12

Add 2 to both sides

y = 3x - 12 + 2

y = 3x - 10

5 0

3 years ago