$QUADRATIC \: \: RESOLUTIONS \\ \\ \\\\4 {x}^{2} \: + \: 40x \: + \: 84 \: = \: 0 \\ \\ 4 \: ( \: {x}^{2} + 10x + 21) \: = \: 0 \\ \\ 4 \: can \: never \: be \: equal \: to \: \: 0 \\ \\ {x}^{2} \: + \: 10x \: + \: 21 = \: 0 \\ \\ {x}^{2} + \: 7x \: + 3x \: + \: 21 = 0 \\ \\ x(x + 7) + 3(x + 7) = 0 \\ \\ ( \: x + 7 \: ) \: ( \: x + 3 \: ) \: = \: 0 \\ \\ On \: solving \: \: , \: \: \: We \: get \: \: \: \: \: - \\ \\ \\ x \: = \: - 7 \: \: \: or \: \: \: x = \: - 3 \: \: \: \: \: \: \: \: Ans.$

6 0

2 years ago

I need to find the angles of A and B. From what I know, they should be congruent, but I've been stuck for wayyyy to long.

ANTONII [103]

Answer:

Step-by-step explanation:

If I'm not mistaken, the 76 degrees means that a is equal to 76 deg. Just visually, if you were to widen that angle, similarly, a would grow just as much.

If you know that a = 76d, b = 76d as well

8 0

2 years ago