<span>Let y represent the original price of the game. Write an expression that can be used to determine the final cost of the game.
(1 - 0.12) y (1 + 0.06)</span>
Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the afternoon drawn from N in a point
ANSWER

EXPLANATION
Let R be the radius of the bigger circle and r, be the radius of the smaller circle.
Then their ratio is given as,

We can rewrite it as fractions to get,

We make R the subject to get,

The area of the bigger circle can be found using the formula,

This implies that,


But it was given in the question that, the area of the bigger circle is 27π.

We divide through by 9π to get,

This means that,

The area of the smaller circle is therefore

-22.55 i think i used a cal but all u do is subtract the percentage with the number