Answer:
Step-by-step explanation:
Given that,
y' = 17y ( 1-y^7)
Let y=1
Then, y' = 0 for all t
Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.
So, the graph solution will be
y(0) = 1 and this will be an horizontal line
If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.
Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.
So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.
This make the limit be 1.
This shows that x = 1 is a stable equilibrium.
It's A and C, I've taken a test that has this question and it was correct when I answered this, so A and C is your answer.
8 x 2 + 6x + 5=0
16 + 6x + 5=0
6x+21=0
6x+21-21=0-21
6x=-21
6x/6=-21/6
x=-7/2
Answer:
20 adults and 10 children
Step-by-step explanation:
We need to find the total amount of adults and children for 30 total people (adults + children) and only 100$ for them. 30 adults is 120$. We need to take off double the amount of money that would bring it to 100$ because the cost for each child is half of an adult. That way, we have 80$ of adults, and when we fill in the rest with children, we get to 100$ total and 30 total people.
X/4 + 12 = 5
to isolate the variable the first step is to subtract 12 from both sides
x/4 + 12 - 12 = 5 - 12
x/4 = -7
next, to get rid of the division by 4, multiply both sides by 4
(x/4)*4 = -7*4
x = -28
