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Sever21 [200]
4 years ago
8

What is 2/5 multiplied by 80 as a mixed number

Mathematics
2 answers:
Dovator [93]4 years ago
7 0

Answer:

32

Step-by-step explanation:

80(2/5) = 160/5 = 32.  This is a whole number.  There's no mixed number here.

pishuonlain [190]4 years ago
4 0

Answer:

this cannot be given as a mixed number it is 32 ...

Step-by-step explanation:

2/5*80/1

160/5

hope that helps! :)

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AveGali [126]

Answer:

(-4,3)

Step-by-step explanation:

8 0
2 years ago
243^-y=(1/243)^3y*9^-2y<br><br><br> a.) y=-1<br> b.) y=0<br> c.) y=1<br> d.) no solution
allochka39001 [22]
243^{-y}=(\frac{1}{243})^{3y}\times 9^{-2y} has y = 0 as a solution.

Selection B is appropriate.
8 0
3 years ago
Read 2 more answers
The probability of flu symptoms for a person not receiving any treatment is 0.038. In a clinical trial of a common drug used to
alexgriva [62]

Answer:

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1164, p = 0.038

So

\mu = E(X) = np = 1164*0.038 = 44.232

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = 6.5231

Estimate the probability that at least 47 people experience flu symptoms.

Using continuity correction, this is P(X \geq 47 - 0.5) = P(X \geq 46.5), which is 1 subtracted by the pvalue of Z when X = 46.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.5 - 44.232}{6.5231}

Z = 0.35

Z = 0.35 has a 0.6368

1 - 0.6368 = 0.3632

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

6 0
3 years ago
If Jenny has 20 donuts and she gives away 10 how many does she have left?
stiks02 [169]
10 donuts to be exact
8 0
3 years ago
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"let v be the event that a computer contains a virus, and let w be the event that a computer contains a worm. suppose p(v) = 0.1
morpeh [17]

Here we might have to find p(v intersection w) and for that we use the following formula

p(v U w) = p(v)+p(w)-p(v intersection w)

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Substituting these values in the formula, we will get

0.14 = 0.13 +0.04 -p(v intersection w)

p(v intersection w) =0.13 +0.04 -0.14 = 0.03

So the required answer of the given question is 0.03 .

7 0
3 years ago
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