Question

"let v be the event that a computer contains a virus, and let w be the event that a computer contains a worm. suppose p(v) = 0.13, p(w) = 0.04, and p(v ∪ w) = 0.14. round the answers to two decimal places."

Answer 1

Here we might have to find p(v intersection w) and for that we use the following formula

p(v U w) = p(v)+p(w)-p(v intersection w)

And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .

Substituting these values in the formula, we will get

0.14 = 0.13 +0.04 -p(v intersection w)

p(v intersection w) =0.13 +0.04 -0.14 = 0.03

So the required answer of the given question is 0.03 .