Question

How to distribute this problem: (x-8)^2 + 16

Answer 1

Answer:

We conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

Step-by-step explanation:

Given the equation

$\left(x-8\right)^2\:+\:16$

First, solve (x - 8)²

Apply Perfect Square formula:    (a - b)² = a² - 2ab + b²

$a=x,\:\:b=8$

$\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2$

             $=x^2-16x+64$

so the expression becomes

$\left(x-8\right)^2+16=x^2-16x+64+16$

                     $=x^2-16x+80$           Add the numbers: 64+16=80

Therefore, we conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$