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lisov135 [29]
3 years ago
7

Is 640 ft or 0.5 mi greater?

Mathematics
2 answers:
Ray Of Light [21]3 years ago
6 0
0.5 a mile is greater because 1 mile is equal to 5,280 ft.

5,280 / 2 = 2,640 ft.
Juliette [100K]3 years ago
5 0
0.5 is bigger than 640 feet
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The surface areas of two similar solids are 1183 and 2023. If the volume of the larger solid is 2333, find the volume of the sma
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A = square root of 1183
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Further samples,
<span>Rounding off numbers to their nearest mentioned position allows approximation from the number value itself. </span>

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4 0
2 years ago
4 bracelets on Thursday and 3 on Friday she uses 5/6 yard for each bracelet
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Answer:

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Step-by-step explanation:

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A company manufactures a 14-ounce box of cereal. Boxes are randomly weighed to ensure the correct amount. If the discrepancy in
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Step-by-step explanation:

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Read 2 more answers
Write a rule to describe each transformation
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Answer:

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Step-by-step explanation:

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2 years ago
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
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