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3 years ago

Write the following fraction as a decimal. A. 1.10 B. 10.1 C. 0.1 D. 0.01

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

7 0

A) 1.1/1=11/10

B)10.1/1=101/10

C).1/1=1/10

D).01/1=1/100

you put the number you have to multiply the decimal with to get a whole n.o as the decimal

Hope you found this answer useful

zloy xaker [14]3 years ago

6 0

Answer:

1/10 as a decimal would be C.) 0.1

Hope I could help! :)

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Answer:

Step-by-step explanation:

x% of y equals to 0.01*x*y

Just put the numbers in the formula

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3 years ago

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Elaine mellon earns $17.80 an hour as an electronic billing specialist for a legal clinic. she must work ____ hours a week, to e

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$17.80 in 1 hr

$1 in 1/17.80 hr

$675.00 in 675.00/17.80 hr

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The distance between two cities is 145 miles. A truck can cover this distance in 2. 5 hours. A car is 1. 5 times as fast as the

Sophie [7]

The relative speed of the car to the truck while moving towards each other is the sum of the speed of both vehicles.

The time it takes them to meet is 1 hour

Reasons:

The distance between the cities, d = 145 miles

The time it takes a truck to cover the distance = 2.5 hours

The speed of the car = 1.5 × Th speed of the truck

Required:

The time it takes them to meet if they are moving towards each other.

Solution:

$\displaystyle Speed = \mathbf{ \frac{Distance}{Time}}$

$\displaystyle Speed \ of \ the \ truck, \ v_{truck} = \frac{145 \ miles}{2.5 \ hours} = \mathbf{58 \ mph}$

Therefore;

The speed of the car, $v_{car}$ = 1.5 × 58 mph = 87 mph

At the time, t, the truck and the car meet, we have;

$\mathbf{v_{car} \times t + v_{truck} \times t = d}$

Which gives;

87 × t + 58 × t = 145

$\displaystyle t = \mathbf{\frac{145}{87 + 58}} = 1$

The time it takes them to meet, t = 1 hour

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2 years ago

Which number satisfies the inequality? 3/11 < x <sqrt 0.25 A. 30% B. 7/9

olya-2409 [2.1K]

Wait what do you mean

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3 years ago

A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year. This situation

lubasha [3.4K]

Answer:

This situations represents the depth of the lake after t years.

The rate of decay is equal to 0.02 a year.

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take 5.77 years for the depth of the lake to reach 26.7 meters.

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the decay of an amount is given by:

$D(t) = D(0)(1-r)^t$

In which D(0) is the initial amount and r is the decay rate, as a decimal.

A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.

This means that $D(0) = 30, r = 0.02$

$D(t) = D(0)(1-r)^t$

$D(t) = 30(1-0.02)^t$

$D(t) = 30(0.98)^t$

This situation represents

The depth of the lake after t years.

The rate of growth or decay, r, is equal to

The rate of decay is equal to 0.02 a year.

So the depth of the lake each year is times the depth in the previous year.

1 - 0.02 = 0.9

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take between years for the depth of the lake to reach 26.7 meters.

This is t for which D(t) = 26.7. So

$D(t) = 30(0.98)^t$

$26.7 = 30(0.98)^t$

$(0.98)^t = \frac{26.7}{30}$

$\log{(0.98)^t} = \log{\frac{26.7}{30}}$

$t\log{(0.98)} = \log{\frac{26.7}{30}}$

$t = \frac{\log{\frac{26.7}{30}}}{\log{0.98}}$

$t = 5.77$

It will take 5.77 years for the depth of the lake to reach 26.7 meters.

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3 years ago