Determine whether the system of linear equations has one solutions, no solution, or infinitely many solutions.

Mathematics

1 answer:

Verdich [7]3 years ago

5 0

Answer:

no solutions

Step-by-step explanation:

same slope different y intercepts

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Someone please help me

Cloud [144]

Answer:

r=12

Step-by-step explanation:

Look, we can reverse the problem to get 23-11=r. This means that r=12.

6 0

3 years ago

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If a common logarithm is written without a base, what base should be used in evaluating it?

Mice21 [21]

10 is the default base for a logarithm
log of 50 is equal to log base 10 of 50

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4 years ago

I need hard and easy math questions with the answer, i need 10 questions<br><br>thnx

nydimaria [60]

Answer:

https://www.khanacademy.org/

Step-by-step explanation:

I am not entirely sure what you mean however if you sign up for this website and go to whichever grade level you need you can practice all you want

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2 years ago

The mean life of a particular brand of light bulb is 1200 hours. if you know that at about 95% of this brand of bulbs will last

Snowcat [4.5K]

<span>204
First, lookup a standard normal table and see what the z-score is for 0.025 (one half of 100% - 95%) to allow for equal sized tails. You should find that the z-score is 1.96. That means that 95% of the time, the value should be within 1.96 standard deviations of the mean. Now let's calculate the standard deviation. 800 is 800 - 1200 = -400 to the left of the mean of 1200. 1600 is 1600 - 1200 = 400 to the right of the mean of 1200. So we are an equal distance of 400 on both sides of the mean. And we know from the z-score of 1.96, that we're 1.96 standard deviations from the mean. So a little division will give us the standard deviation. Which is: 400 / 1.96 = 204.0816327
So the standard deviation of the light bulbs is 204</span>

4 0

3 years ago

University dean is interested in determining the proportion of students who receive some sort offinancial aid. rather than exami

vladimir2022 [97]

The confidence interval is
$0.59\pm0.081$

We first find p, our sample proportion. 118/200 = 0.59.

Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
Subtract from 1: 1-0.98 = 0.02
Divide by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
$ME=z\sqrt{\frac{p(1-p)}{n}}
\\
\\=2.33\sqrt{\frac{0.59(1-0.59)}{200}}=2.33\sqrt{\frac{0.2419}{200}}\approx0.081$

This gives us the confidence interval
$0.59\pm0.081$

8 0

3 years ago