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astraxan [27]
3 years ago
6

the second term in a geometric sequence is 50. The fourth term in the same sequence is 112.5. what is the common ratio in the se

quence?
Mathematics
2 answers:
Finger [1]3 years ago
4 0
Geometric sequence

a_n=a1r^{n-1}
r=common ratio
a1=first term
n=which term

2nd term is 50
4th is 112.5

a_2=a1r^{2-1}=50
a_2=a1r^{4-1}=112.5

50=a1r^{1}
112.5=a1r^{3}

therefor
112.5/50=\frac{a1r^3}{ar^1} =r^2=2.25
r^2=2.25
sqrt both sides
r=1.5

the common ratio is 1.5
vekshin13 years ago
4 0

Answer:

1.5 apex answer

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At a bakery, Victor makes 20 cupcakes. He puts themin equal rows with 10 cupcakes in each row. Whichcalculation can be used to f
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2 sin^2 (x) -5 sin (x) -3=0
andreyandreev [35.5K]

we have that

2sin^{2} x-5sin x-3=0

I. Rewrite the equation by substituting the expression u in for sin x.

2u^{2} -5u-3=0

II. Factor the quadratic expression. Rewrite the equation with factors instead of the original polynomial.

2u^{2} -5u-3=0 is equal to

using a graph calculator-----> see the attached figure

(u-3)*(2u+1)=0

III. Use the zero product property to solve the quadratic equation.

(u-3)*(2u+1)=0

(u-3)=0--------------> u=3

(2u+1)=0-------- 2u=-1------> u=-1/2-----> u=-0.5

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sin x=-0.50------>is the solution

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sin x=-0.50

if the sine is negative

then

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we know that

sin 30°=0.50

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the solution for the III quadrant is

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the solution for the IV quadrant is

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