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PolarNik [594]
3 years ago
13

If k = √31 and m = √26, which graph most closely represent the locations of K and M on a number line? The options are in the pic

ture below..

Mathematics
1 answer:
Dmitry [639]3 years ago
8 0

Answer:

First option

Step-by-step explanation:

√31 = 5.56....

√26 = 5.09....

So m is less than k but greater than 5.

k is greater than k but less than 6.

So the first option is more logical

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María compró 78 metros de cuerda, ella dividió en 6 partes iguales la cuerda el día martes 8 de mayo ¿Cuántos metros mide cada t
barxatty [35]

Answer:

The length of each piece is 13 m.

Step-by-step explanation:

Maria bought 78 meters of rope, she divided the rope into 6 equal parts on Tuesday, May 8, How many meters is each piece?  

a) Each piece measures 312m

c) Each piece measures 13m

d) each piece mites 92m

b) Each piece measures 9m and 75cm

Total length, L =  78 m

Number of pieces, n = 6

length of each piece,

d = L/n = 78/6 = 13 m

So, the correct option is (c).  

6 0
3 years ago
Deepak spent 178$ on food last month if he reduces by 15% the next month how much will he spend
weeeeeb [17]
He will spend $66.3 because 78 times 15/100 (which is 15%) is 11.7, and since he reduces the food you will have to subtract 11.7 from $78, to get $66.3
5 0
3 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
Si f(1)=18 que es f(5)
alexira [117]
F(5)=90 pienso que si
3 0
3 years ago
I need help with this one can someone show me step by step
Gelneren [198K]

Answer:

A

Step-by-step explanation:

You are given one angle and one side are similar

 for  Angle-Side-Angle     you obviously need one more angle attached to the given side

A  angle r = ~ angle c

5 0
2 years ago
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