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2 years ago

What is the measure of Angle P Q R?

Mathematics

2 answers:

lys-0071 [83]2 years ago

5 0

Answer:

Step-by-step explanation:

PQR is 74 degrees

Because PQR is a vertical angle with extended QP and RP side. And vertical angles are always equal

julsineya [31]2 years ago

3 0

55 degrees is the answer

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If p =1/3 and Q=1/4.Evaluate 2p-3Q/12pQ

mixer [17]

Answer:

I got -0.09...

although I could be wrong, don't take my word for it, it's been a while lol

7 0

2 years ago

Which expression is equivalent to 5(d+1) A 5d+5 B 5d+1 C d+5 D d+6

In-s [12.5K]

Hopes this helps:

Answer:

A: 5d+5

8 0

3 years ago

A bag of mixed nuts has 14 almonds, 12 cashews, and 18 peanuts. If one nut is selected, what is the probability that a peanut is

LUCKY_DIMON [66]

18 / 44 = 9 / 22

There are 44 nuts in the bag, and 18 of them are peanuts. If you simplify the fraction, you get 9/22 chance of getting a peanut.

7 0

3 years ago

Read 2 more answers

Scott Harris can invest $7,000 in a 1-year CD that earns interest at an annual rate of 4 percent compounded monthly. The amount

Tom [10]

Answer:

option A is answer.

Step-by-step explanation:

Amount of interest earned for compounded monthly for $1 = 1.040742

Amount of interest earned for compounded quarterly for $1= 1.040604

Difference for $1 = 1.040742 - 1.40604

=0.000138

Difference for $7000 = $7000x0.000138

= 0.966

or $0.96

8 0

3 years ago

Look at this cone: ,,

Assoli18 [71]

Slant height=l=3ft
Radius=r=2ft

We know

$\boxed{\sf \star TSA_{(Cone)}=\pi r(r+\ell)}$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=2 \dfrac{22}{7}\times 2(2+3)$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{44}{7}(5)$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{220}{7}$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=31.4ft^2$

Now

New slant height =2(3)=6cm
New radius=2(2)=4cm

$\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{22}{7}\times 4(4+6)$

$\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{88}{7}(10)$

$\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{880}{7}$

$\\ \sf\longmapsto TSA_{(New\:Cone)}=125.7cm^2$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{125.7}{31.4}$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{4}{1}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cone)}}:{TSA_{(Old\:Cone)}}=4:1}}}$

7 0

3 years ago